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Jackofknives
Cuddle bear inside Topics: 101 Posts: 890 
A man and woman are both affected by an autosomal dominant disorder that has 80% penetrance in all affected individuals. They are both heterozygotes for the diseasecausing mutation. What is the probablity that they will produce phenotypically normal offspring?  
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NNL
Awaitin The Unexpected Topics: 779 Posts: 6613 
.25% i hope i m right but in any case Jack Can u plz post the answer and the explanation that goes along with it.  
doc179
Forum Guru Topics: 67 Posts: 1213 
25% would have been the answer if it had 100% penetrance but since it has 80% penetrance so that would be 40 % unaffected and 60% affected. Hope I am right.  
MALUKO
Forum Newbie Topics: 0 Posts: 7 
Probability that the child will be affected is (.75)(.80) = .60 Probability that the child will not be affected 1  .60 = .40 I only know it because I got it wrong.  
bzhishk
Forum Newbie Topics: 0 Posts: 2 
0.25+(0.75x0.20)=0.4 or 40 %  
Jackofknives
Cuddle bear inside Topics: 101 Posts: 890 
MALUKO wrote: Probability that the child will be affected is (.75)(.80) = .60 Probability that the child will not be affected 1  .60 = .40 I only know it because I got it wrong. This is the explanation.  
the seeker
Forum Newbie Topics: 2 Posts: 3 
great explanation..thanks so much  
Ig F
Forum Guru Topics: 3 Posts: 500 
oh god!!!1i wish i cud solve any of these questions on my own one day>>>>>>  
hitesh
. Topics: 64 Posts: 1112 
This exact question is in kaplan notes as well.  
alirizvi
Forum Newbie Topics: 36 Posts: 542 
good Q.. i did .25 + .20  
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