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Author10 Posts
  #1

A man and woman are both affected by an autosomal dominant disorder that has 80% penetrance in all affected individuals. They are both heterozygotes for the disease-causing mutation. What is the probablity that they will produce phenotypically normal offspring?




  #2

.25% i hope i m right but in any case Jack Can u plz post the answer and the explanation that goes along with it.


  #3

25% would have been the answer if it had 100% penetrance but since it has 80% penetrance so that would be 40 % unaffected and 60% affected. Hope I am right.


  #4

Probability that the child will be affected is (.75)(.80) = .60

Probability that the child will not be affected 1 - .60 = .40

I only know it because I got it wrong. grin


  #5

0.25+(0.75x0.20)=0.4 or 40 %


  #6

MALUKO wrote:
Probability that the child will be affected is (.75)(.80) = .60

Probability that the child will not be affected 1 - .60 = .40

I only know it because I got it wrong. grin


This is the explanation.


  #7

great explanation..thanks so much


  #8

oh god!!!1i wish i cud solve any of these questions on my own one day>>>>>>sad


  #9

nod This exact question is in kaplan notes as well.



  #10

good Q.. i did .25 + .20 disapproval





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