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reet
Forum Guru  Topics: 152 Posts: 1396 |
TWO Inbred mouse strains A and B EXPRESS DIFFerent alleles only at minor histocomapatibility locus on Y chromosome. which of the following mice would accept a skin graft from male (AXB)F1 mouse with strain A father and strain B mother? A.. (AXB)F1 female (A Mother ,B father) b. (AXB)F1 Female( A father, B mother) c (AXB) F1 male( A mother, b FAther) d (AXB) F1 male (A. father B mother)
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sarika
| Forum Guru  Topics: 193 Posts: 1188
b? 
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msyamp
| Forum Guru Topics: 61 Posts: 1449
a father has Y with say A so YA. so the male child get YA.type of HLA. if we give him the graft from chiocie D malechild of YA father. he has YA too. so it would be accepted. so I go for D
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vamsi2004
| Forum Senior Topics: 7 Posts: 143
can someone plz explain this q..
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vanshita
| Forum Guru  Topics: 33 Posts: 950
answer D because male (AXB)F1 mouse with strain A father and strain B mother have genotype xy in which y carry defective alle same thing in option D has AXB) F1 male (A. father B mother) he has genotype xy from which he can accept graft i hope you r not confused
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young_doc
| Forum Guru  Topics: 59 Posts: 718
i say D just cuz it's the same genetic make-up as the host! (hence increase change of graft success) host: male (AXB)F1 mouse with strain A father and strain B mother donor in answer D: (AXB) F1 male (A. father B mother) It seems like the natural answer to me!
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fongch
| Forum Elite  Topics: 71 Posts: 307
Yeah...D essentially describe the same cross scheme as in the stem.
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gafat
| Forum Newbie Topics: 1 Posts: 11
I will go for B. The incompatability is on Y and if the recipent is a female, then, she couldent mount an incomatable gene as she doesent have Y.
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