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TWO Inbred mouse strains A and B EXPRESS DIFFerent alleles only at minor histocomapatibility locus on Y chromosome. which of the following mice would accept a skin graft from male (AXB)F1 mouse with strain A father and strain B mother?
A.. (AXB)F1 female (A Mother ,B father)
b. (AXB)F1 Female( A father, B mother)
c (AXB) F1 male( A mother, b FAther)
d (AXB) F1 male (A. father B mother)
a father has Y with say A so YA. so the male child get YA.type of HLA. if we give him the graft from
chiocie D malechild of YA father. he has YA too. so it would be accepted.
so I go for D
can someone plz explain this q..
because male (AXB)F1 mouse with strain A father and strain B mother have genotype xy in which y carry defective alle
same thing in option D has AXB) F1 male (A. father B mother)
he has genotype xy from which he can accept graft
i hope you r not confused
i say D just cuz it's the same genetic make-up as the host! (hence increase change of graft success)
host: male (AXB)F1 mouse with strain A father and strain B mother
donor in answer D: (AXB) F1 male (A. father B mother)
It seems like the natural answer to me!
Yeah...D essentially describe the same cross scheme as in the stem.
I will go for B.
The incompatability is on Y and if the recipent is a female, then, she couldent mount an incomatable gene as she doesent have Y.
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