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Author	7 Posts
ssrpk Forum Junior Topics: 154 Posts: 2850	May 13, 2005 - 1:37 AM       #1 A patient with a hemoglobin of 10gm/dL and an uncorrected reticulocyte count of 12% has a corrected reticulocyte count of a) 2% b) 4% c)6% d) 8% e) 12%
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SDK Forum Fanatic Topics: 537 Posts: 1586	May 13, 2005 - 3:32 AM       #2 correctable reticulocyte count = Hct/45 x reticulocyte count. Hct???
ssrpk Forum Junior Topics: 154 Posts: 2850	May 13, 2005 - 4:13 AM       #3 u got the formula correct, why not proceed?
ssrpk Forum Junior Topics: 154 Posts: 2850	May 13, 2005 - 4:14 AM       #4 remember the rules of 3!!!!!!!!!!
SDK Forum Fanatic Topics: 537 Posts: 1586	May 13, 2005 - 4:28 AM       #5 just guess.... answer is D...(Hct...30)
ssrpk Forum Junior Topics: 154 Posts: 2850	May 13, 2005 - 4:30 AM       #6 correct- Hb X 3 is approx. Hct
SDK Forum Fanatic Topics: 537 Posts: 1586	May 13, 2005 - 5:00 AM       #7 thnx for this nice info.....Hb x 3 = Hct.

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