sumith
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a solution of glutamic acid is titrated from ph 1.0 to 7.0 by the addition of 5 ml of solution of 1M NaOH. what is the approximate number of millimoles of aminoacid in the sample(pK1=2.19,pK2=4.25,pK3=9.67)?
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| dariush
Forum Elite
Topics: 20
Posts: 356
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let me get my calculator....
r u joking this is a math Q.
where did you get this Q?
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| BumbleB
Forum Junior
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Posts: 83
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is it 0.005 b/c pH=7?
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| mash
Forum Fanatic
Topics: 147
Posts: 1,326
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0.07mmol
wats the ans?
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| sumith
Forum Newbie
Topics: 2
Posts: 10
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sorry for the delay. I got this q from a (pre test book ) written by a prof at U of Texas.I wish if somebody could help me to get the answer in a simple way. I am going to write the answer given in that book.I wish if somebody could explain it better. Answer: To reach Ph 7 approx 100% of alfa carboxyl group(pK alfa1=2.19) and 90% of the alfa carboxylgroup(pKalfa2=4.25) of glutamic acid must be dissociated.At that pH approx twice the amount of NaOH as glutamic acid molecules has been utilized to titrate the two carboxyl groups.Since each ml of a 1M NaOH contain 1 mmol of OH ion about 3mmol of the amino acid is present. :roll:
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| Malaysian
Forum Guru
Topics: 28
Posts: 778
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If I get this sort of question on the boards I'm just going to make a wild guess and save my 10min calculating something which may eventually be wrong!
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| aftabnadim
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hi iam aftab nadeem and i want full curse subjects detail of MSc biochemistry and the scope of biochemistry and the jobs related to it
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