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Author4 Posts
  #1

30 yr old man is phenotypically normal. his 2 siblings died from Tay sachs an AR disese that is lethal by age 5. what is the risk that the man is hyterozygous for the disease causing mutation?
1. 1/4
2. 1/2
3. 2/3
4. 3/4
5. not elevated above that of general population.

This is a Q bank question. But I am not satisfied with the explanation and answer. can some one give an answer and explain please?

  #2

ANS IS 2/3
its an AR ds
his 2 sibs died frm taysachs => both his parents are heterozygous fr mutant allele
then 4 possible combs wud be AA, Aa,Aa and aa
coz he does not ve tay sachs we can ignore aa(==> he is either carrier or normal)
we r left with AA, Aa andAa
risk of being a carrier wud be 2/3

___________________
I hear and I forget. I see and I remember. I do and I understand.
--Confucius

  #3

Yes it is 2/3..good explanation mash!!!

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"Read Repeat Recall Remember Recognise & Reproduce"

  #4

actually when i was doin this question,i dint understand the explanation,but now i do,ur a genius.







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