kalsam
Forum Elite
Topics: 31
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Tay sach's dis, an autosomal recessieve disease caused by a deficienc of Hexosaminidase a, is lethal in childhood. In a population of Ashkenazi Jews, blood testing shows the frequency of heterozygotes to be 0.1.
waht is the probabilty that the first child of two individuals from this population with no family history of the disease will have Tay sachs????
a.0.25
b.0.11
c.0.0625
d.0.0025
e. Cannot be calculated from the information given.
Again answer with explanation pleeeeeese 
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| usmleasr
Forum Guru
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Posts: 970
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it is 0.0025.
becos...it is AR disease..means if both parents r carriers there is 25% chance of child to be affected...that is 0.25..and probablity of afther being carrier is 0.1 and mother 0.1...becso both belong to that population...so
0.1x0.1x0.25 = 0.0025
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| kalsam
Forum Elite
Topics: 31
Posts: 361
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Thanks usmleasr!!!
It was clear..guess i have to play with many questions like this to make myself clear!!!
Thanks agian : )
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| elsa
Forum Junior
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I really do not understand it can you explain to me the explanation of meg? Please :|
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elsa
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