rida
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A man and woman are both affected by an autosomal dominant disorder that has 80% penetrance in all affected individuals. They are both heterozygous for the disease causing mutation. What is the probability that they will produce phenotypically normal offspring?
A) 20%
B) 25%
C) 40%
D) 60%
E) 80%
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| mash
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20%
80% of 1/4(homozygous normal)
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| piter
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C) 40%
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| mash
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wats d ans?
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| dr.shar
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C) 40%
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| crista
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25%-homozygous---80% of 25%=disease=20%
80% phenotype normal
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| mash
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isnt it an aut dom ds?
then, 4 possibilities wud be
AA, Aa,Aa,aa
only aa wud be phenotypically normal
dat means 3/4 wud be diseased...........
if penetrance is 80%,then it is 80/100*3/4=60%
so chances of them having normal offspring r 40%.
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I hear and I forget. I see and I remember. I do and I understand.
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| rida
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You guys are rite, the answer is 40%
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| crista
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right-it's dominant.
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