clar697 Forum Guru

Topics: 190 Posts: 199
| | 07/22/08 - 07:21 AM  
 
|   #1 |
A 45-year-old man comes to the emergency department after inadvertently taking an overdose of metoprolol. His pulse is 40/min and blood pressure is 80/50mmHg. Glucagon is administered intravenously. Five minutes later, his pulse is 70/min and blood pressure is 130/80mmHg. Which of the following best describes the mechanism of action of glucagon in this patient? A) Inhibition of cardiac muscarinic 2 (M2) receptors B) Inhibition of phosphodiesterase C) Opening of K+ channels D) Potentiation of drug-induced hypoglycemia E) Stimulation of adenylyl cyclase
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| md99381 Forum Newbie
Topics: 0 Posts: 3
| | 07/24/08 - 11:56 PM  
 
|   #2 |
e
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| winnera Forum Senior
Topics: 21 Posts: 86
| | 09/18/08 - 07:26 AM  
 
|   #3 |
any deeper explanation?
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| usmlekiller Forum Guru

Topics: 18 Posts: 1,011
| | 09/18/08 - 08:06 AM  
 
|   #4 |
e
___________________ FUTURE 99ER
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| eddyheart Forum Newbie
Topics: 0 Posts: 18
| | 10/02/08 - 08:41 PM  
 
|   #5 |
answer=E Glucagon binds to the glucagon receptor, a G protein-coupled receptor located in the plasma membrane. The conformation change in the receptor activates G proteins, a heterotrimeric protein with α, β, and γ subunits. The subunits breakup as a result of substitution of a GDP molecule with a GTP mol, and the alpha subunit specifically activates the next enzyme in the cascade, adenylate cyclase.
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