mash Forum Fanatic
Topics: 147 Posts: 1,326
| | 04/24/04 - 09:52 AM  
 
   
 
|   #1 |
a man is affected with tyrosinase-negative oculocutaneous albinism (autosomal recessive). Based on this information alone, what is the probability that his grandson and his great-granddaughter are both heterozygous carriers of the albinism gene? can anyone ans this with an explanation?
___________________ I hear and I forget. I see and I remember. I do and I understand. --Confucius
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| Malaysian Forum Guru
Topics: 28 Posts: 778
| | 08/22/04 - 09:59 AM  
 
   
 
|   #2 |
I don't think its possible to calculate as there isn't ample information.
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| nyimg Forum Newbie
Topics: 9 Posts: 30
| | 09/17/04 - 03:15 PM  
 
   
 
|   #3 |
Since he has it (aa), his child that delivered his grandson must be a carrier (at least). So his grandson should have 1/2 probability and his greatgranddaugther should have 1/4 probablity as a carrier.
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| dxtxpx Forum Guru
Topics: 259 Posts: 1,233
| | 09/17/04 - 11:30 PM  
 
   
 
|   #4 |
well according to this site, the answer is 1/8 and they didnt give any explanation: http://medgen.genetics.utah.edu/tests/test11995/q...
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| Ahab Forum Elite
Topics: 9 Posts: 228
| | 09/18/04 - 02:15 AM  
 
   
 
|   #5 |
Because they are asking the probality of both happening 1/2 *1/4 =1/8
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| Mars-Aris Forum Elite

Topics: 71 Posts: 259
| | 09/18/04 - 03:16 AM  
 
   
 
|   #6 |
here is my explanation : 1.all of his children will be carriers 2.50% of his grandchildren willl be heterozygus NO matter the female mate genotype (= if she is carrier, homozygus for recessive or dominant genes) 3.the same situation also for next generation calculating --> 1/8
___________________ determination...& passion
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