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NBME-3 q
Kaplan Test Prep and Admissions (Kaptest.com)




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Author7 Posts
  #1

need ans to this .....


Attached Files:
12.docx (77 KB, 13 downloads)

  #2

the same file in a better format...


Attached Files:
NBME-3.doc (90 KB, 14 downloads)

  #3

look at the graph.
First try to read the graph.

the MODE is easiest to find. Its your EYES test.

the middle 5th and 6th patients are 1.0 and is the mode

same goes for median as they are the average of 2 would be 1

the mean is affected by the maximum values as you can visualize that the maximum values are on the maximum side....

so definitely the mean would be greater than mode and median .




  #4

I just looked at the question again. Its very simple one.
Just find out the median which is very easy. And then look on both sides of median. If the values on right differ a lot from median as compared to left then the distribution is negatively skewed

and vice versa. Answer is A


  #5

so the ans should be A.......THANKS....... the answer provided is "b"........which is wrong then..


  #6

one q....when i looked at the data carefully....i dint find any graphs of equal size.....so i couldnt decide about the mode.........what if a sample doesnt have a mode coz all values are different......would that still be a "gaussian" curve? coz i was wondering about option E too......


  #7

WaqasQureshi wrote:
I just looked at the question again. Its very simple one.
Just find out the median which is very easy. And then look on both sides of median. If the values on right differ a lot from median as compared to left then the distribution is negatively skewed

and vice versa. Answer is A

nod Agree








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