anne
Forum Elite
Topics: 41
Posts: 348
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43. β-Hexosaminidase is made up of α and β subunits. Tay-Sachs disease is due to a mutation in the α-subunit gene, and Sandhoff disease is due to a mutation in the β subunit gene. If a carrier of Tay-Sachs disease marries a carrier of Sandhoff disease, what is the probability that their first child will have either disease?
A ) 0%
B ) 12.5%
C ) 25%
D ) 50%
E ) 100%
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| crista
Forum Guru
Topics: 121
Posts: 408
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0%-heterozigote for both
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| asmi
Forum Hero
Topics: 1043
Posts: 4,609
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Crista how did you conclude that its 0%
:roll: i was thinking its 25%
Anne whats the answer ?
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| anne
Forum Elite
Topics: 41
Posts: 348
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we dont have the answer
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| crista
Forum Guru
Topics: 121
Posts: 408
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i'm sorry-i'm wrong
it's 0% to have either disease but 25% to be a carrier for both
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| jalabert
Forum Newbie
Topics: 0
Posts: 30
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I agree with 0%. Both are heterozygous carrriers. Let's say the carrier for the alpha mutation transfers that mutation, and the carrier for the beta mutation transfers that mutation, the offspring will still have the functional alpha and beta subunits from each of the wild type parents. So, 0%.
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| asmi
Forum Hero
Topics: 1043
Posts: 4,609
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:cry:
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