usmle04 Forum Junior
Topics: 7 Posts: 23
| | 04/05/04 - 10:59 PM  
 
   
 
|   #1 |
The following nunbered codons relate to partial sequence of mRNA for a protein. termination codons are UAg, UGA, UAA ; initiation codon AUG. The triplets are numbered as shown: 132 133 134 135 136 137 138 139 UUG CUG CCA UAU UGU UGU GUU AAU Inerstion of uridine between end of codon 135 & beginning of 136 will result in a protein containing how many amino acids? A) 134 B) 135 C) 136 D) 137 E) 138
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| Idiopathic Forum Guru
Topics: 19 Posts: 641
| | 04/05/04 - 11:09 PM  
 
   
 
|   #2 |
the answer should be 138. If you insert any nucleotide in the sequence, then you will come across a stop codon (UAA) at AA 139. THis will result in a 138-AA peptide. remember, there are three stop codons: UAA, UAG, UGA
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| usmle prep Forum Senior
Topics: 21 Posts: 100
| | 04/06/04 - 12:28 AM  
 
   
 
|   #3 |
I agree with Idiopathic,ans is E)
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| usmle04 Forum Junior
Topics: 7 Posts: 23
| | 04/07/04 - 09:32 AM  
 
   
 
|   #4 |
Thanks
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