sudipto1973 Forum Newbie
Topics: 4 Posts: 31
| | 04/02/04 - 08:18 AM  
 
   
 
|   #2 |
Fractional excretion of sodium is excreted load of sodium divided by filtered load of sodium or to put it in other way FeNa+ = (V X UNa+) / (GFR X PNa+) where V is urine flow rate and PNa+ and UNa+ are plasma and urine Na+ conc. In pre-renal failure due to decreased renal perfusion the kidneys try to conserve as much sodium so as to increase plasma volume and hence renal perfusion. So FENa+ will be less in pre-renal failure compared to intrinsic renal failure. I don't remember the values though.
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| usmleasr Forum Guru
Topics: 105 Posts: 970
| | 04/02/04 - 08:24 AM  
 
   
 
|   #3 |
thanks good explanation..FENa+ less than 1%is typical of pre-renal failure.. in renal (ATN)FENa+ is greater than 2% due to failure to reabsorb
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