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Author8 Posts
  #1

A sample of purified oligopeptide sequence was treated with cyanogen bromide. The original sequence is NH3—Gly-Arg-Phe-Lys-Met-Asp-Tyr-Ala-Arg-Met-Glu—COO— Which of the following is the appropriate cleavage product?

A. Gly-Arg-Phe-Lys-Met/Asp-Tyr-Ala-Arg-Met/Glu

B. Gly-Arg-Phe/Lys-Met-Asp-Tyr/Ala-Arg-Met-Glu

C. Gly-Arg/Phe-Lys/Met-Asp-Tyr-Ala-Arg-Met-Glu

D. Gly/Arg-Phe-Lys-Met-Asp-Tyr-Ala/Arg-Met-Glu

E. Gly/Arg-Phe-Lys-Met-Asp-Tyr-Ala-Arg-Met-Glu

  #2

the ansis A,please explain to me if someone can figure out how this is the ans.

  #3

it is a tough Q anne..but i remember someone explained it before..they said the enzyme/whatever will break at only Met group . :roll:

  #4

asmi look at the lippincott's bio, p 16.

  #5

thanks peter will surely look at it .

wow they have given a nice diagram.... my fault for not reading biochem :oops:

  #6

Was there any information that you can share asmi

  #7

Well, In lippincott, the diagram indicates that Cyanogen Bromide cleaves a peptide at the C-terminal of Methionine.

Thus, the answer is A

  #8

Thanks Usmle4me smiling face







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