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NBME-3 qs 17
Kaplan Test Prep and Admissions (Kaptest.com)




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Author4 Posts
  #1

Two experimental drugs, drug X and Y, are being evaluated for the treatment of Congestive heart failure. patients receiving drug X hv a cardiac index of 2.5 L/m2 with a 95% confidence interval of 1.5 to 3.5. patients recvng drug Y hv a cardiac index of 1.7 L/m2 with a CI of 0.7 to 2.7. A test of the significance of diff shows a p-value of 0.1. which of the foll. is the liklihood that the diff in mean cardiac index of patients recvng drug X and drug Y is due to chance ?

A. 0%
B. 2.5%
C. 5%
D. 7.5%
E. 10%
F. 66.7%
G. 95%

confused


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  #2

p-value of 0.1

so D 10%

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Yea how I feel studying for this test!

  #3

nod

  #4

so hard q and so easy to answer rolling eyes







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