new_n_lost Politically InCorrect

Topics: 653 Posts: 6,118
| | 10/06/07 - 05:55 PM  
 
   
 
|   #1 |
A new antifungal medication is being tested in Phase I clinical trials. Examination of the pharmacokinetic properties of the drug reveals that the half-life of the drug is 6 hours. If a continuous intravenous infusion of this drug were started on a research subject, how long would it take to reach 75% of steady state? A. 3 hours B. 6 hours C. 9 hours D. 12 hours E. 18 hours F. 24 hours
___________________ FORUM RULES-- Those who believe in telekinesis, raise my hand. I get enough exercise just by pushing my luck --P4U World.." The pure and simple truth is rarely pure and never simple."
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| hope4dabest Forum Elite

Topics: 17 Posts: 434
| | 10/06/07 - 06:46 PM  
 
   
 
|   #2 |
D
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| icandoittoo Forum Senior
Topics: 20 Posts: 73
| | 10/09/07 - 02:57 PM  
 
   
 
|   #3 |

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| DRFP Forum Senior

Topics: 10 Posts: 168
| | 10/27/07 - 06:07 PM  
 
   
 
|   #4 |

___________________ you only fail when you give up!
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| imnalini Forum Senior
Topics: 10 Posts: 127
| | 11/12/07 - 07:10 AM  
 
   
 
|   #5 |
sumbody xplain.................
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| milee99 Forum Guru
Topics: 44 Posts: 1,010
| | 11/14/07 - 11:46 PM  
 
   
 
|   #6 |
pls explain
___________________ Do not pray for easy lives,Pray to be stronger men; Do not pray for tasks equal to your powers, Pray for powers equal to your tasks; Then the doing of your work shall be no miracle, but you shall be the miracle.
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| milee99 Forum Guru
Topics: 44 Posts: 1,010
| | 11/15/07 - 12:48 AM  
 
   
 
|   #7 |
for continuous infusion, concentration of drug in plasma at time t is given by Cp=[K0/(V.kel)] [1-e^(-kel.t)] where k0 is infusion rate , kel is elimination constant =0.693/(t1/2) , e is the logarithmic e, V is volume of distribution also steady state conc at continuous infusion Cpss=k0/(kel.V)=k0/Clearance substitute 75%cpss =3/4*k0/(kel.V) in first equation e^(-kel.t)=0.25=1/4 so, e^(kel.t)=4 taking log, log e 4= kel.t so, log e (2^2)=2(log e 2)=kel*t that was log 4 to base e kel=0.693/(t1/2)=0.693/6=(log e 2 )/6 so, substitute ,2 (log e 2 )=[(log e 2)/6] * t t/6=2 t=12 so , 12 hrs i donno if we have to kn ow all these formulas its not in kaplan its not in katzung plus we need log knowledge refreshed people i hope u all answered it by sum clear logic please explain if yes
___________________ Do not pray for easy lives,Pray to be stronger men; Do not pray for tasks equal to your powers, Pray for powers equal to your tasks; Then the doing of your work shall be no miracle, but you shall be the miracle.
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| new_n_lost Politically InCorrect

Topics: 653 Posts: 6,118
| | 11/15/07 - 01:34 AM  
 
   
 
|   #8 |
hope4dabest wrote: D
 
___________________ FORUM RULES-- Those who believe in telekinesis, raise my hand. I get enough exercise just by pushing my luck --P4U World.." The pure and simple truth is rarely pure and never simple."
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| new_n_lost Politically InCorrect

Topics: 653 Posts: 6,118
| | 11/15/07 - 01:35 AM  
 
   
 
|   #9 |
Its quite simple actually The correct answer is D. The rule of thumb is that the plasma concentration will reach 50% in one half-life, 75% in two half-lives, 87.5% in three half-lives, etc., so that the difference between the current drug level and 100% halves with each half-life. In this instance, it takes two half-lives to reach 75%. The half-live of this drug is 6 hours, so two half-lives is 12 hours.
___________________ FORUM RULES-- Those who believe in telekinesis, raise my hand. I get enough exercise just by pushing my luck --P4U World.." The pure and simple truth is rarely pure and never simple."
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| new_n_lost Politically InCorrect

Topics: 653 Posts: 6,118
| | 11/15/07 - 01:45 AM  
 
   
 
|   #10 |
Katzung Board Review Pg 23 Figure 3-3 7th ed. Explains it well. Kaplan 2004ed. pg 14 explains the Steady state effects. The trick in this question was the continuous infusion whereas if we look at the graph given in Kaplan Fig 1-1-18 explains it all. If a single bolus was given the plasma conc wud have decreased by 50% every 6 hrs now if the infusion was going at a steady state the after 6 hrs the drug falls to 50% of initial conc. and after another 6hrs the state becomes half of infused drug in 6hrs plus the leftover in the plasma.
___________________ FORUM RULES-- Those who believe in telekinesis, raise my hand. I get enough exercise just by pushing my luck --P4U World.." The pure and simple truth is rarely pure and never simple."
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| new_n_lost Politically InCorrect

Topics: 653 Posts: 6,118
| | 11/15/07 - 01:48 AM  
 
   
 
|   #11 |
The tricky word was Continous infusion now if it were asked wht wud be the time taken to achieve the 75% of the required steady state we all wud have reached the answer.
___________________ FORUM RULES-- Those who believe in telekinesis, raise my hand. I get enough exercise just by pushing my luck --P4U World.." The pure and simple truth is rarely pure and never simple."
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| milee99 Forum Guru
Topics: 44 Posts: 1,010
| | 11/15/07 - 04:13 PM  
 
   
 
|   #12 |
right thanks i got confused d/t continuous infusion and got psyched out wid this equation
___________________ Do not pray for easy lives,Pray to be stronger men; Do not pray for tasks equal to your powers, Pray for powers equal to your tasks; Then the doing of your work shall be no miracle, but you shall be the miracle.
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| milee99 Forum Guru
Topics: 44 Posts: 1,010
| | 11/15/07 - 04:14 PM  
 
   
 
|   #13 |

___________________ Do not pray for easy lives,Pray to be stronger men; Do not pray for tasks equal to your powers, Pray for powers equal to your tasks; Then the doing of your work shall be no miracle, but you shall be the miracle.
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| Ig F Forum Elite

Topics: 3 Posts: 436
| | 11/25/07 - 12:15 PM  
 
   
 
|   #14 |
thnx nnl..u made it sound really easy.......D is the correct answer 
___________________ i m not perfect but i wanna get close to it......
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