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Author9 Posts
  #1

Five percent of individuals of a particular population are known to carry a recessive gene for poliodystrophy, an inherited disorder characterized by the onset of recurrent seizures and dementia early on in childhood. A 32 year old woman who had a brother with this disease seeks genetic counselling . The patient's husband. is an only child and does not know if his family had a history of this disorder. What is the probability that this patient is a carrier of poliodystrophy?

a.1/20
b.1/10
c.3/8
d.2/3
e.3/4

  #2

her brother has the disease implies both of her parents r carriers..
so she can be eithe normal or carrier ...only 2 possiblities..
so probablity is 2/3 :roll:

  #3

iam also thinking in terms of 2/3....but we have to consider that 5 % population thing..

:cry: why don't i understand it...very bad of myself.. :cry:

  #4

Both of you...well done!.....the answer is D...2/3...i got it right too......but it was a difficult question...and the answer is even more confusing....

Well.......... the 32 year old woman had a brother with the disease which means that the parents were heterozy carriers.....Now that means...the woman can either be a genotypically normal homzyg or a hetero carrier like her parents.....

So probability that she is a healthy homozy is 3/4.....and the probability that she is a carrier is 1/2

so probability of being just a carrier = 1/2 / 3/4

=2/3

confusing answer?...

  #5

thanks for the explanation

  #6

what would be the chance of the child being affected by this disease?

  #7

i think there will be 25% chance of having normal / affected child.

  #8

are you sure?
what about:
2/3 (for mother) * 5/100 (for father)=1/30?

  #9

if the disease is AR,

chances of

mom being a carrier 2/3
father being a carrier 5/100

mom passing the gene 2/3 x 1/2 = 1/3
father passing the gene 5/100 x 1/2 = 5/200

thus the kid being affected 1/3 x 5/200 = 5/600 = 1/120









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