asmi
Forum Hero
Topics: 1043
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a man and women both having autosomal dominant disease , have 80% penetrance .They both are heterozygous.What is the probablity that they will have a normal baby ?
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| usmleasr
Forum Guru
Topics: 105
Posts: 970
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40%?? :?:
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| Colombia
Forum Guru
Topics: 85
Posts: 438
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25%
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| asmi
Forum Hero
Topics: 1043
Posts: 4,609
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since it is a autosomal dominant disease there is 75% risk to the offsprings ( 50% chance..to receive 1 copy and 25 % chance to receive 2 copies)
with 80% penetrance 0.75 x 0.8 = 0.6 or 60%
The probablity that they will have phenotypically normal babies is 1-0.60 = 0.40 or 40%
:roll: i thing which i didn't understand is from where did they get 1 .
if anyone can explain it to me...iam a dumb student . :oops:
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| jayesh
Forum Junior
Topics: 2
Posts: 46
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the 1 is nothing but 100%
its like this, out of 100%(1) , chance of likely getting ds is 60%(0.6)
therefore chance of likely not getting ds is 100-60 = 40% or 0.4
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| asmi
Forum Hero
Topics: 1043
Posts: 4,609
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thanks
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