po
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4. In a population that is in Hardy-Weinberg equilibrium, the frequency of the homozygous recessive genotype is 0.09. What is the frequency of individuals that are homozygous for the dominant allele?
a.0.7
b.0.21
c.0.42
d.0.49
e.0.91
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| usmletopper1
Forum Junior
Topics: 13
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0.49
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| drgho
Forum Junior
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0.49
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| asha_usmle
Forum Newbie
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Isn't it 0.91
AA=0.09=p
BB=q
p+q=1
therefore q=1-0.09=0.91
plz explain if I'm wrong.
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| amritt786
Forum Senior
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a2 is .09
a will be squer root of .09 ie 0.3
b will 1-.3=0.7
bb will be .49
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| dallas
Forum Junior
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does 'homozygous for the dominant allele' mean the same as homozygous for the normal allele?
i mean if it a recessive condition, why is the dominant allele being asked, i cant understand, someone pl help.
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| sfk
Forum Elite
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yes, in an autosomal recessive condition the normal allele is the dominant allele.
now i cant understand ur question, why cant they ask about the normal allele. IMO they can ask about anything!!
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| SmokyWaters
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