drduck
Forum Guru
Topics: 82
Posts: 523
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as a part of experimental study, a volunteer agrees to have 10 grams of mannitol injected I/V. after sufficient time of equilibration, blood is drawn, and the concentration of mannitol in the plasma is found to be 65mg/100ml.
urine analysis reveals that 10% of the mannitol has been excreted in urine during this time period.
what is the approximate extracellular fluid volume of this volunteer.....
10 L
14 L
22 L
30 L
42 L
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| peraspera
Forum Elite
Topics: 38
Posts: 233
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we injected 10 gr, 10% of it is gone with urine. So we have 9gr of mannitol.
Extracellular fluid volume= quantity of substance administrated/ concentration of substance in compartment
Ext.fluid=0.9/65/100=13.85 or 14L
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| doc179
Forum Guru
Topics: 67
Posts: 1,217
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14L
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| drduck
Forum Guru
Topics: 82
Posts: 523
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good job both of u....
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| ssrpk
Forum Fanatic
Topics: 154
Posts: 2,819
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it should be the answer, just one thing troubling me,
why did'nt we convert the units of mass here from mg to grams or vice versa, why is that exempted???
can someone explain!
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life is guud
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| doc179
Forum Guru
Topics: 67
Posts: 1,217
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V*C=A
V= A/C
V = 9gms * 0.1L / 0.065gms = 14 L.
This is how I arrived to this answer.
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| peraspera
Forum Elite
Topics: 38
Posts: 233
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1. 10gr=10000mg
2. 10% is gone- (10gr-1gr)=9gr, or 9000mg
3. 100ml=0.1L
4. 65/0.1=650mg/L
5. 9000mg /650mg/L=13.846L , or 14L
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