Prep for USMLE 
Forum  Resources  New Posts  Register  Login  » 

Author  9 Posts  
monam84
Forum Senior Topics: 34 Posts: 134 
100 subjects : Genotype number of control AA 30 AB 25 BB 45 What is the frequency of B allele: 25/200,45/200,50/200,90/200,115/200 I picked 45/100+12/100(half of 25)= 115/200, is this correct? Thanks  
Prep4USMLE.com
Advertisement 


monam84
Forum Senior Topics: 34 Posts: 134 
No one?  
doc179
Forum Guru Topics: 67 Posts: 1213 
yes, 45+45+25/200=115/200  
monam84
Forum Senior Topics: 34 Posts: 134 
Thanks, doc  
yoga
usmlelogy professor Topics: 73 Posts: 637 
i didnt get this concept even when i listened 2 audio can some1 explain plz  
NNL
Awaitin The Unexpected Topics: 779 Posts: 6613 
BB= 2* 45 = 90 then AB takeing B as 25 so 90+ 25 = 115 then divide it by the total number of Alleles that 200. They asked Allele Frequency its the simplest form of the question they cud have asked,  
sherry39
Forum Senior Topics: 3 Posts: 104 
heloo  
asha_usmle
Forum Newbie Topics: 2 Posts: 7 
AA 30 AB 25 BB 45 out of 100 subjects therefore, AA 60 AB 50 and BB 90 out of 200 subjects Allele frequency of B = 90 + 25 (i.e half of AB)= 115/200  
mohammem
Forum Newbie Topics: 2 Posts: 198 
AB genotype= 25x1=25,,,,,,,,,,,,,,,1 is one allele in 1 chr BB genotype=45x2(two allele) =90 each chrom. has two copies(fixed principle)so 100 person(who have the chrom. we count its allele) have 200 alleie so 90 +25/200=115/200,,,,,,,,,,,,,,you are right,,,,,,thanks  
Similar forum topics hardy weinberg! Hardy Weinberg hardyweinberg  Related resources 
Advertise  Support  Privacy  TOS  Premium  Contact 