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am-nicole
Forum Newbie Topics: 37 Posts: 129 |
Consider a reaction that can be catalyzed by one of two enzymes ,A and B, with the following kinetics. Km (M)---- ----- -- ------ V max (mmol/min) A. 5 X 1O to the -6 power ------- 20 B. 5 X 10 to the -4 power ------- 30 At a concentration of 5 X 10 to the -4 power M substrate,the velocity of the reaction catalyzed by the enzyme A will be A. 10 B. 15 C. 20 D. 25 E. 30 The answer is C WHY???????? Edited by am-nicole on Feb 15, 2007 - 4:10 PM
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pringo
| Forum Newbie Topics: 1 Posts: 14
Hi dear am-nicole : V= Vm*[S] / Km + [S] so, V= 20*(5*10 power -4 ) / (5*10 power -6) + (5*10 power -4) V= 10 power -2 / 5*10 power -6 (1 + 100 ) , [1+100 ~ 100] (ignor 1) V= 20
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vijay vegesna
| Forum Newbie Topics: 1 Posts: 17
at 5X10 -4(ten to the power -4) A is at Vmax,so 20
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