am-nicole
Forum Junior
Topics: 19
Posts: 61
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Consider a reaction that can be catalyzed by one of two enzymes ,A and B, with the following kinetics.
Km (M)---- ----- -- ------ V max (mmol/min)
A. 5 X 1O to the -6 power ------- 20
B. 5 X 10 to the -4 power ------- 30
At a concentration of 5 X 10 to the -4 power M substrate,the velocity of the reaction catalyzed by the enzyme A will be
A. 10
B. 15
C. 20
D. 25
E. 30
The answer is C WHY????????
Edited by am-nicole on 02/15/07 - 05:10 PM
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| pringo
Forum Newbie
Topics: 1
Posts: 12
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Hi dear am-nicole :
V= Vm*[S] / Km + [S] so,
V= 20*(5*10 power -4 ) / (5*10 power -6) + (5*10 power -4)
V= 10 power -2 / 5*10 power -6 (1 + 100 ) , [1+100 ~ 100] (ignor 1)
V= 20
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| vijay vegesna
Forum Newbie
Topics: 1
Posts: 17
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at 5X10 -4(ten to the power -4) A is at Vmax,so 20
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