macTT
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If the patient survies 2 year after the operation, what is the probablity that the patient will survive the next 4 years?
A) .8
B) .85
C) .84 X .85
D) .62X .8 X .84X .85
E).85 -.8
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| robin082006
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this qs lacks something.
=0.85*0.84*0.76* year 6
Can u post the question agian?
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| macTT
Forum Senior
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Robin,
Thanks for taking the time to help me out....
The question is as follows...... If a patient survives 2 years after the operation, which of the following is the probability of surviving at least 4 years?
Are they independent events?
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| Ancylostoma
Forum Guru
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I think it may be condional probability, look probability theory and you may finr your answer under conditional probability.
Edited by Ancylostoma on 12/20/06 - 04:00 PM
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| robin082006
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answer is C =0.85*0.84
at least 4 years is different from next 4 years.
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The Key to Succeed is Patience.
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| macTT
Forum Senior
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Robin,
Thanks for the help.....but could you possibly show me how you derived the answer? I was thinking D because they are indpendent events? Thanks.
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| Ancylostoma
Forum Guru
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I really didnt notice the change in the question, robin is right , I had been trying to calculate thinking it was the next 4 years which made me think there was something wrong with the problem. .84 is the probabilty of survining the 3rd year given he survied the second. .85 is the probablity of him surviving the 4th year given he survived the 3. Now you multiply the values .85 *.84 and you get the probability
C
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| macTT
Forum Senior
Topics: 32
Posts: 86
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Thx bro for the derivation,
Good luck on your test too.....thanks for everything.....
Best
TT
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