vallia Forum Guru
Topics: 98 Posts: 889
| | 11/15/06 - 12:49 PM  
 
   
 
|   #1 |
17. Two experimental drugs, drug X and drug Y, are being evaluated for treatment of congestive heart failure. Patients receiving drug X have a cardiac index of 2.5 L/m2 with a 95% confidence interval of 1.5 to 3.5. Patients receiving drug Y have a cardiac index of 1.7 L/m2 with a 95% confidence interval of 0.7 to 2.7. A test of the significance of difference shows a p-value of 0.1. Which of the following is the likelihood that the difference in mean cardiac index of patients receiving drug X and drug Y is due to chance? A. 0% B. 2.5% C. 5% D. 7.5% E. 10% F. 66.7% G. 95%
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| fox Forum Guru

Topics: 70 Posts: 727
| | 11/15/06 - 01:04 PM  
 
   
 
|   #2 |
E. 10%. P value = 0.1 means that less than 1 out of 10 Or 10 out of 100 cases are due to chance.
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| vallia Forum Guru
Topics: 98 Posts: 889
| | 11/17/06 - 03:42 AM  
 
   
 
|   #3 |
oau, it was easy but i got confused with the long text..thanks
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