docswapna Forum Senior
Topics: 61 Posts: 229
| | 09/26/06 - 05:23 PM  
 
   
 
|   #1 |
Family with father ,grandfather and grandmother suffering from gardner's syndrome.father has 4 children.what are the chances that atleast one child has inherited the gardner's syndrome allele? A.1/4 B.1/2 C.3/4 D.13/16 E.15/16
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| fox Forum Guru

Topics: 70 Posts: 727
| | 09/26/06 - 05:42 PM  
 
   
 
|   #2 |
U had posted a similar q (wardenburg's). We lesser mortals got stumped. Could u tell us watz the answer for both the Q?
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| docswapna Forum Senior
Topics: 61 Posts: 229
| | 09/26/06 - 08:05 PM  
 
   
 
|   #3 |
for wardenbugs ur right. 1/8 1/2x1/2x1/2 try this. i will post the ans later..
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| alexaE Forum Elite

Topics: 23 Posts: 334
| | 09/27/06 - 12:59 AM  
 
   
 
|   #4 |
here it is E
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| ManuNastai Transilvanian..

Topics: 55 Posts: 838
| | 10/09/06 - 03:26 AM  
 
   
 
|   #5 |
E
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| Palaniappan Forum Senior
Topics: 30 Posts: 148
| | 11/20/06 - 02:41 PM  
 
   
 
|   #6 |
Can anyone exlain the answer E?
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| nrkmani Forum Newbie
Topics: 0 Posts: 3
| | 11/23/06 - 11:30 PM  
 
   
 
|   #7 |
gardener is autosomal dominant. 1 st genereration risk is 50% 2 nd gen risk is 25% (1/4) total probability of all 4 children affected is 1/4 *1/4*1/4*1/4 =1/16 probability of atleast one child affected=1-1/16=15/16
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| drbin Forum Guru

Topics: 27 Posts: 535
| | 12/01/06 - 08:51 PM  
 
   
 
|   #8 |
hw could the risk in first gen be 50 % bs both grandfather and gr mother affected, so chance must be 75%
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| drbin Forum Guru

Topics: 27 Posts: 535
| | 12/01/06 - 09:03 PM  
 
   
 
|   #9 |
Ans E? 1st gen Aa * Aa AA Aa Aa aa So chance that father has diseased allele is 3/4 2nd gen Aa * aa Aa Aa aa aa so risk is 50 % ie 1/2 chance for all 4 to be affected is 1/2 * 1/2 * 1/2 * 1/2 = 1/16 Risk of atleast 1 having disease allele = 1-1/16= 15/16
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