docswapna
Forum Senior
Topics: 61
Posts: 229
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Patient receiving drug X have a cardiac index of 2.5L/m2 with a 95% CI of 1.5 to 3.5. Patient receiving drug Y have a CI of 1.7L/m2 with a 75%CI of 0.7 to 2.7. A test of significance of difference shows a p value of 0.1. Which of the following is the likelihood that the difference in mean cardiac index of pat receiving drug x and y is due to chance.All are%
a 95
b 2.5
c 5
d 7.5
e 10
f 66.7
g 0
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| young_doc
Forum Guru
Topics: 56
Posts: 735
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I was always under the impression that if p>0.05, then we accept the null hypothesis.
So here p=0.1, hence we accept the null hypothesis, and the difference was likely to be caused by chance alone. I would guess A.95%.
I'm just guessing?????????????????????????
Somone please explain =)
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| HILFIGER
Forum Senior
Topics: 22
Posts: 195
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Failure to reject null hypothesis. p value of 0.1 means the 10% likelihood that the difference is due to chance.
So I think correct answer is e
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| suravi
Forum Newbie
Topics: 5
Posts: 19
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Agree with hilfiger, the answer is E
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