In a certain population, the frequency of color-blind males is 1 in 100. Assuming that the population is in Hardy-Weinberg equilibrium at this locus, the frequency of color-blind females is approximately A. 0.0001 B. 0.0005 C. 0.01 D. 0.02 E. 0.025
vanshita Forum Guru
Topics: 25 Posts: 861
09/15/06 - 07:09 AM
#2
D colorul blind is X linked autosomal recessive disease so incidence of disease and gene frequency same so gene frequency 1/100 carrier 2pq q 1/100 p 1-q= 99/100 almost 1 so carrier 2/100=0.02
suv Forum Elite
Topics: 43 Posts: 233
09/15/06 - 09:47 AM
#3
color blindness is an x linked recessive condition so the gene frequency is the proportion of affected males i.e.,1/100 since females have to inherit 2 x chromosomes their gene frequency is 1/100*1/100= 0.0001 so the frequency of colorblind females is 0.0001 answer is A if they ask the frequency of hetrozygotes in females then it is 2*1/100*1/10000
Edited by suv on 09/15/06 - 11:01 AM
___________________ Time is God!
blueocean Forum Senior
Topics: 15 Posts: 195
09/15/06 - 10:55 AM
#4
suv is right!
vanshita Forum Guru
Topics: 25 Posts: 861
09/15/06 - 03:29 PM
#5
suv u r right
rubina Forum Newbie
Topics: 1 Posts: 21
09/20/06 - 03:31 PM
#6
A
ManuNastai
10/09/06 - 03:48 AM
#7
vanshita wrote: D colorul blind is X linked autosomal recessive disease
