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Kaplan Qbank USMLE



Author3 Posts
  #1

Suppose a blood vessel with a blood pressure of 100 mmGh split into two identical branches. One branch , at its end had a pressure of 75 mmHg, while the other branch is lacerated, and open to the atmosphere (pressure of 0mmHg). What is a ratio of the blood flow through the lacerated branch over the intact branch?


a. 1.5
b. 2.
c. 3
d. 4
e. 5

  #2

we know that flow Q

Q = dP/R

since branches are equal (identical diameters ) ,so R is equal in both .It means it is constant.So

Q is directly proportional to dP

dP in the first one = 100 -75 = 25 mm of Hg

dP in the 2nd one = 100 - 0 = 100 mm of Hg

So ratio of flow is 25:100 = 1: 4

So answer is "d"

Best of luck


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FA is just a good revision book.It is not a "real" learning tool.

  #3

Maybe Leopard is right; interesting exlination; I have no clue on the answer and maybe my inquiery is not relevant in this Q, but R shouldn't be equal since a lacerated vessel would contract from reflex (i.e. vascular phase of hemostasis) increasing the resistance and trying to stop the bleeding.

Was just a thought... paranoic thaught, that is!

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