Tiger1974 Forum Newbie
Topics: 12 Posts: 18
| | 09/11/06 - 08:00 PM  
 
   
 
|   #1 |
Suppose a blood vessel with a blood pressure of 100 mmGh split into two identical branches. One branch , at its end had a pressure of 75 mmHg, while the other branch is lacerated, and open to the atmosphere (pressure of 0mmHg). What is a ratio of the blood flow through the lacerated branch over the intact branch? a. 1.5 b. 2. c. 3 d. 4 e. 5
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| Leopard Forum Guru

Topics: 30 Posts: 401
| | 09/11/06 - 08:40 PM  
 
   
 
|   #2 |
we know that flow Q Q = dP/R since branches are equal (identical diameters ) ,so R is equal in both .It means it is constant.So Q is directly proportional to dP dP in the first one = 100 -75 = 25 mm of Hg dP in the 2nd one = 100 - 0 = 100 mm of Hg So ratio of flow is 25:100 = 1: 4 So answer is "d" Best of luck
___________________ FA is just a good revision book.It is not a "real" learning tool.
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| ManuNastai Transilvanian..

Topics: 55 Posts: 838
| | 09/12/06 - 03:42 AM  
 
   
 
|   #3 |
Maybe Leopard is right; interesting exlination; I have no clue on the answer and maybe my inquiery is not relevant in this Q, but R shouldn't be equal since a lacerated vessel would contract from reflex (i.e. vascular phase of hemostasis) increasing the resistance and trying to stop the bleeding. Was just a thought... paranoic thaught, that is!
___________________ "Love is the only inflamation of the heart that drains in the vagina" (translation after Dr Petre Florescu, Professor of Pathology, UMF "Iuliu Hatieganu", Cluj Napoca
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