drpkaur
Forum Guru
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A patient is injected with 25omg of mannitol.At equilibrium,the concentration of mannitol in plasma is 2.5mg/100ml.during the equlibrium period, 5% of the injected mannitol is excreted in urine...what is the patient's ECF volume???
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| dr_sarim
Forum Senior
Topics: 16
Posts: 75
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9000ml...is it ?
of the initial 250 mg. 5% ( 25 mg) is lost in urine so 225 mg
vol. of ECF = amount of tracer /concentration of tracer
=225 (mg) / 0.025 (mg/ml)
=9000ml
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| dr_sarim
Forum Senior
Topics: 16
Posts: 75
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sorry..at equilibrium 5% is lost so
ecf will never the less be 10000 ml
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| alpha12
Forum Senior
Topics: 6
Posts: 70
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if 5% is lost, that means, amount of tracer (A) will be 95% of the initial, 237.5mg
V=A/C
V=237.5/0.025=9500ml
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| dr_sarim
Forum Senior
Topics: 16
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do you have an asnwer dr_pkaur?
i thout the 5% is lost at equilibrium...
confusion confusion ....aaaah
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| alpha12
Forum Senior
Topics: 6
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I'd assume that the concentration of 2.5mg/ml happens after the 5% loss.
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| drpkaur
Forum Guru
Topics: 196
Posts: 810
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ECF volume-amount/concentration
=Amount injected -Amount excreted/conc in plasma=250mg-12.5mg/2.5mg/100ml=237.5/2.5=9500ml
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