zubr
Forum Junior
Topics: 14
Posts: 61
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Q:If the chance of surviving for 1 year after being diagnosed with prostate cancer is 80% and the chance of surviving for 2 years is 60%, what is the chance of surviving for 2 years given that the patient is alive at the end of the first year?
(A) 20%
(B) 48%
(C) 60%
(D) 75%
(E) 80%
Answer: WHY?
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| robin082006
Forum Hero
Topics: 471
Posts: 5,125
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C
this patient is alive at the end of the first year, so probability of surviving for 2 years= 100%*60%=60%
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| reet
Forum Fanatic
Topics: 152
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Good Robin
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| Ivil
Forum Senior
Topics: 8
Posts: 169
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isnt it D?
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| alexaE
Forum Elite
Topics: 23
Posts: 334
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it is D, b/c he made it the first year so he's among the 80% and he is making it a second year so among the new 60%
so its 60% out of the 80: 60/80= 75%
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| nadiabarati
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agree with alexaE
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| zubr
Forum Junior
Topics: 14
Posts: 61
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Kaplan gives D but why division ???????
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| tolito
Forum Fanatic
Topics: 119
Posts: 2,164
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i may have a simpler way of looking at it.
8 out of the original 10 survived to year 1
6 out of original 10 survived to year 2. ( which means 6 out of the 8 that survived the first year)
patient is one of the 6. so that makes his probability 6 out of 8. ie 6/8 x 100% = 75%.
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| MRMAVERICK
Forum Guru
Topics: 41
Posts: 742
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d
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