drpkaur Forum Guru

Topics: 195 Posts: 808
| | 06/17/06 - 09:07 PM  
 
   
 
|   #1 |
A flow-volume loop was recorded from a male medical student during a normal tidal volume (normal breathing) and during a maximal expiration (FVC) followed by a maximal inspiration to TLC. If a residual volume (RV) of 2.5 L was measured by indirect gas dilution techniques for this student, total lung capacity (TLC) would be closest to (Hint: What is the FVC of this subject?) A-2.25L B-3.25L C-5.50L D-8.0L E-11.5L PICTURE is attached to it....
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| drpkaur Forum Guru

Topics: 195 Posts: 808
| | 06/20/06 - 08:37 AM  
 
   
 
|   #2 |
hi there,, nobody is going to answer it,so bad...plz try
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| robin082006 Forum Hero

Topics: 471 Posts: 5,125
| | 06/20/06 - 09:41 AM  
 
   
 
|   #3 |
In the figure, TLC=nearly 6 FVC= nearly 4 I do not need RV to calculate TLC in this case, but No correct match with the answer, May be 5.5 is the correct?
___________________ The Key to Succeed is Patience.
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| drpkaur Forum Guru

Topics: 195 Posts: 808
| | 06/20/06 - 10:46 AM  
 
   
 
|   #4 |
. FVC (5.5L) plus RV (2.5L) equal TLC=8.0L
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| robin082006 Forum Hero

Topics: 471 Posts: 5,125
| | 06/20/06 - 11:07 AM  
 
   
 
|   #5 |
According to the chart, TLC=6 , FRV=4, RV=2, right? I do not get the answer, can you please post its explanation?
Edited by robin082006 on 06/20/06 - 11:29 AM
___________________ The Key to Succeed is Patience.
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| drpkaur Forum Guru

Topics: 195 Posts: 808
| | 06/20/06 - 12:16 PM  
 
   
 
|   #6 |
See if you take FVC from the point where TLC is situated that is where the expiration starts ,it closely correlates to 5.5 then RV is already measured it's 2.5 it's given in the question so 5.5 +2.5=8.0L ,is it right..
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| robin082006 Forum Hero

Topics: 471 Posts: 5,125
| | 06/20/06 - 12:43 PM  
 
   
 
|   #7 |
Based on what I learned in Kaplan's, TLC in this case is 6 (or 5.5). and we do not need to add 2.5 I don't get what you explain. I suspect, then review Kaplan, page 247 Physiology, figure VI-1-21, and answer should be 5.5
Edited by robin082006 on 06/20/06 - 06:08 PM
___________________ The Key to Succeed is Patience.
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| robin082006 Forum Hero

Topics: 471 Posts: 5,125
| | 06/20/06 - 12:46 PM  
 
   
 
|   #8 |
From the figure, TKC=6 and RV=2--> FVC=4 FVC in this case is nearly 4. I calculated by calculating the interval within the chart (or = TLC-RV). How you realize FVC in the above figure?
___________________ The Key to Succeed is Patience.
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| drpkaur Forum Guru

Topics: 195 Posts: 808
| | 06/20/06 - 06:05 PM  
 
   
 
|   #9 |
yeah sorry i was also confused then the TLC =6 According to this figure but in options 5.5 is given so 5.5 is the best answer..
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| aim Forum Junior
Topics: 4 Posts: 45
| | 11/21/06 - 12:31 PM  
 
   
 
|   #10 |
i am still confused , how u guys are calculating---------------- i will be veeeerrrry thankful to u , if u he lp me to understand
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| ssrpk Forum Fanatic

Topics: 154 Posts: 2,813
| | 11/21/06 - 05:24 PM  
 
   
 
|   #11 |
look at the chart, and calculate the FVC, by looking at the X-axis, it starts at it starts at 2 and ends at 6, so FVC is the difference between the two which is 4L! add up the RV and u hv the total lung capacity! or simply enough, the max.volume tht is read on the X-axis, is the TLC
___________________ life is guud
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| aim Forum Junior
Topics: 4 Posts: 45
| | 11/22/06 - 08:18 AM  
 
   
 
|   #12 |
thanx a lot
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