dr.gurinder
Forum Junior
Topics: 16
Posts: 24
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800 MOTOR VEHICLE COLLISIONS OCCURED OVER 2 YEARS IN A CITY WITH A POPULATION OF 600000: 600 OF THESE ACCIDENTS WERE ALCOHOL RELATED.DURING THE SAME PERIOD, THERE WERE 400 FATALITIES DUE TO MOTOR VEHICLE COLLISIONS, OF WHICH 75% WERE ALCOHOL RELATED.WHICH OF FOLLOWING BEST REPRESENTS 1 YEAR INCIDENCE OF ALCOHOL RELATED MOTOR VEHICLE FATALITIES IN THIS COMMUNITY?
1.150 PER 600000
2.300 PER 600000
3.450 PER 600000
4.600 PER 600000
5.UNABLE TO DETERMINE FROM AVAILABLE INFORMATION.
PLEASE DESCRIBE YOUR ANSWER.
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| vanshita
Forum Guru
Topics: 21
Posts: 812
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2 300per600000
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| general malaise
Forum Guru
Topics: 14
Posts: 433
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2
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"El respeto al derecho ajeno es la paz" Benito Juarez
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| robin082006
Forum Hero
Topics: 471
Posts: 5,125
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1
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| r_albayunen
Forum Senior
Topics: 0
Posts: 218
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2
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| robin082006
Forum Hero
Topics: 471
Posts: 5,125
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Hi,
300 for 2 years so 150 for 1 year
calculation = (400*75%)/2=150
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| humpf!!
Forum Elite
Topics: 51
Posts: 120
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can it just be ASSUMED that since it was 300 for 2 years, that it would automatically be 150 for 1 year? i have a problem withmaking such assumptions. is this written anywhere?
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| leen
Forum Guru
Topics: 79
Posts: 294
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wat abt the 600 deaths mentioned earlier? r they not to b included?
thanks
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| robin082006
Forum Hero
Topics: 471
Posts: 5,125
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that is a distracter, alcohol-related accidents, not deaths
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| leen
Forum Guru
Topics: 79
Posts: 294
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thanks
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| nadiabarati
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Hey robin you are wonderful. Very careful. Good luck
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| nadiabarati
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I think answer is E.
You CAN NOT simply divide 300/2!! What if we had 200 in one year and 100 in the next year So the incidence in each year would be different while the accumulation would be 300.
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| zubr
Forum Junior
Topics: 14
Posts: 61
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If nothing dramatically changed in this city, and by this Q nothing changed, you can calculate average and it would be true plus/minus z x Standard Error.
Edited by zubr on 06/23/06 - 07:29 PM
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