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Kaplan Qbank USMLE



Author6 Posts
  #1

The probability of Hepatitis B P(D+) in a certain pt population is known to be 0.20 ,conversely P(D-)=0.80 .In a study of new diagnositc test for Hepatitis B, the probability of positive test result among pt's known to have hepatitis B ,P(T+(D+), is shown to be 0.90.,where as probability that healthy pt will have negative result ,P(T-(D-), is shown to be 0.95 .What is the probability that a new pt with a negative test is truly healthy ? A. 0.95 B. 0.95 X 0.80
( 0.95 X 0.80) +(0.5 X0.80) C. .95 X.20
( .95 X.80 )+(.90 X 0.20) D. .95 X.80
( .95 X .80)+(.90 X.20)

E.none


  #2

I think the answer is 76/78

it means E.none


  #3

This q asls about Negative Predictive Value

I have posted the way to calculate it twice in this forum.

ANswer is 76/78, so E.

......................Disease .....................Non-Disease..................... Total

Positive...........18.............................4...................... ..............22

Negative...........2.............................76 ....................................78

Total...............20.............................80.................... ..............100

NPV=76/68


___________________
The Key to Succeed is Patience.

  #4

Hi Robin,

This makes me feel stupid,
but still i couldn't figure out how you calculated TP,FP,TN,FN
I will really really appreciate if You can explain again please.shaking head

  #5

i calculated it as 95/98.....

see TN is .95

TP is .9.....so FP will be .2-(.2x.9)

TN predictive value is TN/TN+FN

hence 95/97.

comments most welcomed


___________________
remedy for weakness is not brooding over it ,but thinking of strength.

  #6

i calculated it as 95/98.....

see TN is .95

TP is .9.....so FP will be .2-(.2x.9)

TN predictive value is TN/TN+FN

hence 95/97.

comments most welcomed


___________________
remedy for weakness is not brooding over it ,but thinking of strength.







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