DrVirgo
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15. Two inbred mouse strains, A and B, express different alleles only at a minor histocompatibility locus on the Y chromosome. Which of the following mice would accept a skin graft from a male (AxB)F1 mouse with a strain A father and a strain B mother? A. (AxB)F1 female (A mother, B father)
B. (AxB)F1 female (A father, B mother)
C. (AxB)F1 male (A mother, B father)
D. (AxB)F1 male (A father, B mother)
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| mangoshaikh
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i think its D
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| doc179
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even before thinking too much about it, I noticed that the details of the donor mouse is the very same as the mouse in choice D. So that is the mouse that is most likely to accept this graft without problems
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| raves
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well i think the answer should be B cos the difference in the alleles is on the y chromosomes n the female in B has only x chromosomes but shares the common parents.
please comment.
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| tolito
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B.
same reason as raves. we know that the MHC is co-dominantly expressed. so if the donor rat does not express the Y gene cos it is female then the incompatible protein will not be expressed and only those from the X from father and X from mother which are compatible will be expressed.
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| study_ing
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im confused..arent they asking about an acceptor rat rather than a donor one?
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| sridevibandaru24
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D
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| study_ing
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any explanation??
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| sridevibandaru24
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The genotype of donor mouse& that of option D are same.so this is the only possibility
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| macleodkc
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The options are for the acceptor rats... so the donor rat we know does have the mutation - because it's on the Y chromo and the donor rat is male- Doesn't this then mean that the acceptor rat must have the mutation... so it must be have the Y chromo... ie. it must be male. Furthermore the difference occurs in the A strain in the donor, so the acceptor can only be A strain Y chromosome... ie. A strain Male father.
So I'm pretty sure the answer is D.
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