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Kaplan Qbank USMLE



Author8 Posts
  #1

TWO Inbred mouse strains A and B EXPRESS DIFFerent alleles only at minor histocomapatibility locus on Y chromosome. which of the following mice would accept a skin graft from male (AXB)F1 mouse with strain A father and strain B mother?

A.. (AXB)F1 female (A Mother ,B father)

b. (AXB)F1 Female( A father, B mother)

c (AXB) F1 male( A mother, b FAther)

d (AXB) F1 male (A. father B mother)


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  #2

b?confused

  #3

a father has Y with say A so YA. so the male child get YA.type of HLA. if we give him the graft from

chiocie D malechild of YA father. he has YA too. so it would be accepted.



so I go for D




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  #4

can someone plz explain this q..

  #5

answer D

because male (AXB)F1 mouse with strain A father and strain B mother have genotype xy in which y carry defective alle

same thing in option D has AXB) F1 male (A. father B mother)
he has genotype xy from which he can accept graft

i hope you r not confused


  #6

i say D just cuz it's the same genetic make-up as the host! (hence increase change of graft success)

host: male (AXB)F1 mouse with strain A father and strain B mother

donor in answer D: (AXB) F1 male (A. father B mother)

It seems like the natural answer to me!


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  #7

Yeah...D essentially describe the same cross scheme as in the stem.

  #8

I will go for B.

The incompatability is on Y and if the recipent is a female, then, she couldent mount an incomatable gene as she doesent have Y.










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