msyamp
Forum Fanatic
Topics: 60
Posts: 1,462
|
E unequal recombination. both X are from mother. no X from father.
if its skewed inactivation of normal X then it would be a random one and need not cause disaese.
___________________
If you think you can You can! If you think you cant you are right again!!
|
| msyamp
Forum Fanatic
Topics: 60
Posts: 1,462
|
now i doubt why cant it be skewed x inactivation?
___________________
If you think you can You can! If you think you cant you are right again!!
|
| robin082006
Forum Hero
Topics: 471
Posts: 5,125
|
D is more suitable
___________________
The Key to Succeed is Patience.
|
| msyamp
Forum Fanatic
Topics: 60
Posts: 1,462
|
yes robin. its D
___________________
If you think you can You can! If you think you cant you are right again!!
|
| nadiabarati
|
can you explain what skewed x inactivation mean?
|
| doc179
Forum Guru
Topics: 67
Posts: 1,217
|
in the female one of the X chromosomes either the maternal or the paternal is inactivated..randomly..and exist as barr bodies and in an X linked disease which generaly affects only male if the normal X chromosome gets inactivated even the female would then suffer from the disease..I think tht is what it means
|
| msyamp
Forum Fanatic
Topics: 60
Posts: 1,462
|
yes doc you are right. here the X from the father is normal.(because son is affected which means X from mother is diseased and father shud have disease if X is diseased as he as only one X)
so in the daughter the X from father is inactivated.SKEWED here means that its a selective inactivation of father's X. even in stats we means it is inclined towards a particular direction it is not equally chanced. here its the same.
___________________
If you think you can You can! If you think you cant you are right again!!
|
| DrVirgo
Forum Hero
Topics: 1083
Posts: 3,465
|
6.
So in this case,-- Hemophilia A (X-linked recessive), the mother is a carrier with one X affected, but she is not diseased.
The father is normal.
If you do a punnet square you will see:
1. One daughter has One affected X, and should be a carrier.
2. Other daughter inherited both normal X's and is not diseased or a carrier.
3. One son has the disease because he inherited the abnormal X from the mom.
4. The other son is normal because he inherited the Normal x from mom and Y from dad....
So now what you are saying is that in order for 1 to be diseased instead of being a carrier, the normal X has to be inactivated? Isn't this random and either X chromosome can be inactivated in different cells (e.g. in some cells the normal one will be inactivated, while in other cells the abnormal one will be inactivated)???
So, how does the daughter have the disease?
Thanks. 
___________________
Our greatest glory is not in never falling, but in rising every time we fall.
|
| study_ing
Forum Fanatic
Topics: 180
Posts: 2,511
|
well inactivation of the x is random and thus, unfortunately the carrier has randomly got greater inaactivation of the normal x -chromosome causing the disease to be manifested despite the heterozygous status
___________________
If you yourself are at peace, then there is at least some peace in the world.
|
| MRMAVERICK
Forum Guru
Topics: 41
Posts: 728
|
ya its d-
|
|
| |
| | | | | | | | | | |
