drk1980 Forum Guru

Topics: 147 Posts: 1,038
| | 01/15/06 - 11:34 AM  
 
   
 
|   #1 |
Aspirin is a weak acid with a Pka of 3.5. At physiologic pH approximately what percentage of aspirin molecules are in the associated form? A. 0.001% B. 0.01% C. 0.1% D. 1% E. 10%
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| msyamp Forum Fanatic
Topics: 60 Posts: 1,462
| | 01/15/06 - 11:47 AM  
 
   
 
|   #2 |
PH = PKA + LOG (BASE/ACID) 7.5 = 3.5 + LOG (BASE/ ACID) LOG BASE/ ACID = 4 LOG BASE/ACID =LOG 10000 BASE / ACID = 10000 BASE IS IONISED AND ACID IS UNIONISED UNIONISED IS .0001
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| msyamp Forum Fanatic
Topics: 60 Posts: 1,462
| | 01/15/06 - 11:47 AM  
 
   
 
|   #3 |
ANSWER IS NOT GIVEN
___________________ If you think you can You can! If you think you cant you are right again!!
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| Doc2378 Forum Guru

Topics: 46 Posts: 688
| | 01/15/06 - 11:56 AM  
 
   
 
|   #4 |
Here I'd go with A Actually from my calculations it is = 1/ 1+ 10000
___________________ Courage does not always ROAR. Sometimes courage is the quiet voice at the end of the day saying, "I will try again tomorrow" - Mary Anne Radmacher
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| msyamp Forum Fanatic
Topics: 60 Posts: 1,462
| | 01/15/06 - 11:58 AM  
 
   
 
|   #5 |
hey tricky one good one. it is .0001 that is .01% that is answer is B. good one drk
___________________ If you think you can You can! If you think you cant you are right again!!
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| Doc2378 Forum Guru

Topics: 46 Posts: 688
| | 01/15/06 - 11:59 AM  
 
   
 
|   #6 |
ooops....good one dude!
___________________ Courage does not always ROAR. Sometimes courage is the quiet voice at the end of the day saying, "I will try again tomorrow" - Mary Anne Radmacher
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| drk1980 Forum Guru

Topics: 147 Posts: 1,038
| | 01/15/06 - 12:01 PM  
 
   
 
|   #7 |
msyamp, good one alright! 
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| DrPak Forum Elite

Topics: 49 Posts: 348
| | 01/16/06 - 07:37 AM  
 
   
 
|   #8 |
Actually, you don't need to calculate it... all those log calculations looks really scary. Anthony Trevor gave a much easier way. He said: If the difference b/w the pH and pK is more than 2, then the the ratio (b/w ionized and non-ionized) will be 99.99:0.01. If the difference is 2, then the ratio will be 99:1. If the difference is 1 then the ratios will be 90:10. If the difference is 0, then the ratio is 50:50. In the question, the difference was >2, so immediately I thought that one form, either the ionized or non-ionized must be 99.99 and the other must be .01.
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| drk1980 Forum Guru

Topics: 147 Posts: 1,038
| | 01/16/06 - 09:26 AM  
 
   
 
|   #9 |
thts even better!
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| Geroo Forum Guru
Topics: 114 Posts: 799
| | 01/16/06 - 02:20 PM  
 
   
 
|   #10 |
Drpak,so if the difference b/w PH and PK is 3 or 4 or 5,the ionized non ioniized ratio will be the same 99.99 : .01?
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| Doc2378 Forum Guru

Topics: 46 Posts: 688
| | 01/16/06 - 04:38 PM  
 
   
 
|   #11 |
Thats pretty useful DrPak...Thanks! Also, if like me....the log scale scares you, you guys can try: A-/HA = 10^(PH-Pka), where ^ denotes 'raised to the power'
___________________ Courage does not always ROAR. Sometimes courage is the quiet voice at the end of the day saying, "I will try again tomorrow" - Mary Anne Radmacher
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| DrPak Forum Elite

Topics: 49 Posts: 348
| | 01/16/06 - 09:09 PM  
 
   
 
|   #12 |
The difference will not be much more than 2 because if it were you would be dealing with a strong acid or base, and we don't use such compounds in medicine. The physiological pH is always the same, its just the pK of the drug that changes. As you can imagine, if the difference was 5, then it means the pK of the drug must be something like 2 (if it's acidic) or 12 (if its basic). That's pretty strong stuff.
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| Geroo Forum Guru
Topics: 114 Posts: 799
| | 01/16/06 - 09:22 PM  
 
   
 
|   #13 |
in this question the difference is almost 4.what if the the pk of the drug was 4.5 instead of 3.5.what is the ionized non ionized raio in this case using your rule?
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| DrPak Forum Elite

Topics: 49 Posts: 348
| | 01/16/06 - 11:04 PM  
 
   
 
|   #14 |
The difference would still be more than 2. The answer would be the same. Can someone calculate this to confirm?
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