JAS Forum Junior
Topics: 11 Posts: 33
| | 01/13/06 - 12:56 PM  
 
   
 
|   #1 |
please see in the attached
Attached Files:
Qestion in genetics.doc (56 KB, 52 downloads)
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| drk1980 Forum Guru

Topics: 147 Posts: 1,038
| | 01/13/06 - 01:14 PM  
 
   
 
|   #2 |
i'll venture with D On second thots, i'll go by A!!
Edited by drk1980 on 01/13/06 - 01:22 PM
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| msyamp Forum Fanatic
Topics: 60 Posts: 1,462
| | 01/13/06 - 01:22 PM  
 
   
 
|   #3 |
i go with d. because duchenne's is x linked. father carrier and son got it. drk you aregood
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| drk1980 Forum Guru

Topics: 147 Posts: 1,038
| | 01/13/06 - 01:26 PM  
 
   
 
|   #4 |
msyamp, but DMD is X-linked. so i ruled out D coz if that embryo is a male he cant be a 'carrier' , he'll be affected. If its a female then she wud hv got the lower band from mother and upper from dad. And the lower band of the mothers is not the mutant one....and dad doesnt hv it. So thts ruled out. Heck the Q says mother doesnt hv the mutant dystrophin...so iam wondering who's kid it is!
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| msyamp Forum Fanatic
Topics: 60 Posts: 1,462
| | 01/13/06 - 01:31 PM  
 
   
 
|   #5 |
ya maan same with me. i dint thnk of felony or adultration here. but i though some DMD traits that can also be transferred in x linked dominant way. yes
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| reet Forum Fanatic

Topics: 152 Posts: 1,411
| | 01/13/06 - 01:37 PM  
 
   
 
|   #6 |
what about choice C??
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| anjushree Forum Guru
Topics: 64 Posts: 386
| | 01/13/06 - 01:55 PM  
 
   
 
|   #7 |
i think ans is A
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| reet Forum Fanatic

Topics: 152 Posts: 1,411
| | 01/13/06 - 02:18 PM  
 
   
 
|   #8 |
post the answer with explaination
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| JAS Forum Junior
Topics: 11 Posts: 33
| | 01/13/06 - 02:42 PM  
 
   
 
|   #9 |
I even do not und The correct answer is E. Duchenne muscular dystrophy<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /> (DMD) is an X-linked recessive disease typically affecting only males. Females who inherit the disease-producing gene are usually unaffected carriers. In this family, the mother is a carrier of the DMD gene. Comparing her RFLP pattern to her affected son shows that the top (larger) fragment in her pattern is a surrogate marker for the DMD gene. The lower (smaller) fragment in her pattern is a surrogate marker for her normal allele. (Note that in the unaffected father, genetically unrelated to the mother, the top fragment is a marker for his normal gene.) Three embryos will produce phenotypically unaffected children: Embryo 1 (a female homozygous for the normal allele), Embryo 3 (a male), and Embryo 4 (a female carrier). Only Embryo 2 will produce a male with DMD. Embryo 4 will produce a carrier female who is not affected (thus eliminating choices A and C). Embryo 3 (choice B) will produce a normal male without the DMD allele. Embryo 1 (choice D) will be a female carrier of the DMD allele. Embryo 1 is homozygous for the normal allele. erstand the answer, how can people know the sex of child. See the answer:
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| msyamp Forum Fanatic
Topics: 60 Posts: 1,462
| | 01/13/06 - 02:49 PM  
 
   
 
|   #10 |
good one not to boast. thought of that. but i thought i was thinking a ot. good one
___________________ If you think you can You can! If you think you cant you are right again!!
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| JAS Forum Junior
Topics: 11 Posts: 33
| | 01/13/06 - 02:51 PM  
 
   
 
|   #11 |
How can you know the sex of embryos?
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| reet Forum Fanatic

Topics: 152 Posts: 1,411
| | 01/13/06 - 02:56 PM  
 
   
 
|   #12 |
oh okayyyy,,,i was confused about choice C- 4 embryo.. GOT UR ANSWER. thanks jas fr posting this question.
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| reet Forum Fanatic

Topics: 152 Posts: 1,411
| | 01/13/06 - 02:57 PM  
 
   
 
|   #13 |
X linked disease---so son will be affected... so which band matches with DAD.. I THINK SO.
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| msyamp Forum Fanatic
Topics: 60 Posts: 1,462
| | 01/13/06 - 02:59 PM  
 
   
 
|   #14 |
sex is know by the fact that in x linked disorders. if you have two alleels it is she. if you have one allel it is he
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