drk1980
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If the compliance of a person's lung is 0.5 L/cm H2O and intrapleural pressure is -10cm H2O. What is the new intrapleural pressure if this person exhaled 1.0L?
Plz display ur work-up.
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| msyamp
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-10CM IS PRESSURE
AND COMPLIANCE = VOL CHANGE/PRESSURE CHANGE
0.5 = 1.0 LIT /NEW PRESSURE - (-10CM)
THE PRESSURE DIFF = 1.O / 0.5
THE PRESSURE DIFF IS 2
SO THE NEW PRESSURE IS 2CMH2O LESS OR DECREASED AS IT IS INSPATION THE PRESSUR INCREASES. SO IT IS - 8 CM H2O
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| robin082006
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good explanation msyamp
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| sturge_weber
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yep -8
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| drk1980
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thanks a lot! btw, u do mean new pressure is 'increased' by 2cm H2O, rite? patient is exhaling..
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| msyamp
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yes. that what is given in the quest
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