roopashri
Forum Elite
Topics: 16
Posts: 190
|
<?xml:namespace prefix = st1 ns = "urn:schemas-microsoft-com:office:smarttags" />Tay sach's dis, an autosomal recessieve disease caused by a deficienc of Hexosaminidase a, is lethal in childhood. In a population of Ashkenazi Jews, blood testing shows the frequency of heterozygotes to be 0.1. what is the probabilty that the first child of two individuals from this population with no family history of the disease will have Tay sachs????
a.0.25
b.0.11
c.0.0625
d.0.0025
e. Cannot be calculated from the information given<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" />
|
| Doc2378
Forum Guru
Topics: 46
Posts: 688
|
D?
Since 2pq= 1/10
therefore probability of mating of 2 heterozygotes from the population = 2pq x 2pq= 1/100
Probability of aa from an Aa x Aa cross= 1/4
Combined probability = 1/4 x 1/100 = .0025
Edited by Doc2378 on 12/24/05 - 08:55 PM
___________________
Courage does not always ROAR. Sometimes courage is the quiet voice at the end of the day saying, "I will try again tomorrow" - Mary Anne Radmacher
|
| Geroo
Forum Guru
Topics: 114
Posts: 799
|
yes answer is D.
|
| satyaking
Forum Junior
Topics: 5
Posts: 58
|
yes answer is D 1/400 that is 0.0025
|
| roopashri
Forum Elite
Topics: 16
Posts: 190
|
good job friends..
|
|
| |
| | | | | |
