dinesh sharma Forum Newbie
Topics: 1 Posts: 9
| | 12/12/05 - 11:27 AM  
 
   
 
|   #1 |
I
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| dinesh sharma Forum Newbie
Topics: 1 Posts: 9
| | 12/12/05 - 11:29 AM  
 
   
 
|   #2 |
If distribution of Xlinked recessive trait is 1 in 500, and the disease causes sterility in effected males then what is the carrier rate?
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| msyamp Forum Fanatic
Topics: 60 Posts: 1,462
| | 12/12/05 - 11:45 AM  
 
   
 
|   #3 |
Males A=normal a=diseased Females AA or Aa = normal aa= diseasd Females Frequency Males Frequency AA p2 A p Aa 2pq a q = 1/500 aa q2 From males, q=1/500 therefore p=499/500. Female carriers =2pq =2 x 499/500x 1/500 =998/250000 almost 1000/250000 or 1 in 250
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| sturge_weber Forum Guru
Topics: 77 Posts: 1,042
| | 12/12/05 - 12:19 PM  
 
   
 
|   #4 |
yes as msyamp said. q=1/500. so carrier frequency=2pq= 2x1/500x1=1/250
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| dinesh sharma Forum Newbie
Topics: 1 Posts: 9
| | 12/12/05 - 06:22 PM  
 
   
 
|   #5 |
I dont think so, the 2pq is derived from the fact that alleles are received from mother and father both. I think the answer should be q only i.e. 1 in 500. I heard the question from someones exam experience , so not sure about the answer.
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| msyamp Forum Fanatic
Topics: 60 Posts: 1,462
| | 12/12/05 - 06:32 PM  
 
   
 
|   #6 |
http://employees.oneonta.edu/bachman/human%20gene...
___________________ If you think you can You can! If you think you cant you are right again!!
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| zhoufg Forum Senior
Topics: 15 Posts: 112
| | 12/21/05 - 11:57 AM  
 
   
 
|   #7 |
I agree that q=1/500, 2pq=1/250. only carrier female x normal male= infertility male which is q=1/500.
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