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Kaplan Qbank USMLE



Author7 Posts
  #1

I


  #2

If distribution of Xlinked recessive trait is 1 in 500, and the disease causes sterility in effected males then what is the carrier rate?




  #3

Males A=normal
a=diseased

Females AA or Aa = normal
aa= diseasd

Females Frequency Males Frequency
AA p2 A p
Aa 2pq a q = 1/500
aa q2

From males, q=1/500 therefore p=499/500.

Female carriers =2pq =2 x 499/500x 1/500 =998/250000

almost 1000/250000 or 1 in 250


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If you think you can You can! If you think you cant you are right again!!

  #4

yes as msyamp said. q=1/500.

so carrier frequency=2pq= 2x1/500x1=1/250


  #5

I dont think so, the 2pq is derived from the fact that alleles are received from mother and father both. I think the answer should be q only i.e. 1 in 500. I heard the question from someones exam experience , so not sure about the answer.

  #6

http://employees.oneonta.edu/bachman/human%20gene...

___________________
If you think you can You can! If you think you cant you are right again!!

  #7

I agree that q=1/500, 2pq=1/250. only carrier female x normal male= infertility male which is q=1/500.








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