robin082006
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A patient with a hemoglobin of 10gm/dL and an uncorrected reticulocyte count of 12% has a corrected reticulocyte count of
a) 2%
b) 4%
c)6%
d) 8%
e) 12%
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| Doc2378
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d
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| reet
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d) 8%
Hct = hb x 3( rule of 3 in goljan notes)=30%
corrected reticulocyte count = ( Hct/45 ) x reticulocyte count
= 30/45x12
=8%
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| Geroo
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| sturge_weber
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good going reet
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| robin082006
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you got it
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