kpochily Forum Newbie
Topics: 1 Posts: 1
| | 08/28/05 - 05:42 AM  
 
   
 
|   #1 |
I am having trouble figuring out how to do probability problems in my genetics class. I need help in figuring out an easier way of doing them. For example: Consider the offspring in a cross of two AaBbCcDdEe parents. Compute the probability for the following offspring: a) AAbbCCee b) aabbccddee c) aABbccDDee d)A-B_ccddE-(where A-=AA or Aa) the problem I am having is, I need an easier way of doing this sort of problem. The way I do it now is I write out all possible phenotypes, maybe I am doing it wrong. So, maybe you could show me that also. If anyone can help me with this type of problem it would be greatly appreciated. P.S. Sorry, I know I posted this in the wrong area but I am still new to this and don't know how to determine where my thread will post. Thank you in advance for any help that ANYONE can lend on this issue.
Edited by kpochily on 08/28/05 - 05:47 AM
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| ssrpk Forum Fanatic

Topics: 154 Posts: 2,814
| | 09/09/05 - 02:56 PM  
 
   
 
|   #2 |
i don't get the question! if u are asking about probability of offspring with homozygosity(AA or aa) by 2 parents with genotype Aa, then the probability would be simply 25% or 0.25, now inorder to have joint probabilities of four independent events ,multiply all the probabilities together for eg. 0.25 X 025 X 0.25 X 0.25!
___________________ life is guud
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| Flying h4x0r Forum Junior

Topics: 4 Posts: 51
| | 09/10/05 - 10:51 AM  
 
   
 
|   #3 |
you don't have to write out all the phenotypes, do what ssprk said For example, the probabilty of (c) aABbccDDee would be: Aa x Aa, probability of Aa is 0.50 Bb x Bb, probability of Bb is 0.50 Cc x Cc, probability 0f cc is 0.25 Dd x Dd, probability of DD is 0.25 Ee x Ee, probability of ee is 0.25 mutliply 0.5 x 0.5 x 0.25 x 0.25 x 0.25 = 0.0039, or 0.39%
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