kaash110
Forum Senior
Topics: 17
Posts: 57
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Hardy Weinberg. If the number of homozygotes is 1/4900, can you tell me the number of heterozygotes
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kaash
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| 2002tii
Forum Senior
Topics: 5
Posts: 80
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According to Hardy Weinberg: p^2 + 2pq + q^2 = 1. In this case q^2 = 1/4900, so q = 1/70. Thus p = 69/70, so number of heterozygotes is 2pq, which is 2*(69/70)*(1/70) = 138/4900 ~ .028
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