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Kaplan Qbank USMLE



Author8 Posts
  #1

55 yr old male visit complaint of urinary infrequency.Exam: reveal 1 cm nodule on his prostate gland..PSA result is 7 ng/ml while normal is 4 ng/mlwhich is 80% sensitivety & 90% specificity..A cross sectional study show that 10% of this age group has prostate cancer....man has actual % of prostate cancer is??
a)13%
b)36%
c)47%
d)69%
e)81%
Explain the answer in detail???

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  #2

try to answer it.

PSA is positive

Prostate cancer None cancer

PSA+ 80 10

PSA- 20 90

this question is asking positive predictive value, so answer is TP/TP+FN=80/80=10

closeset answer is E.

Am I right?


  #3

80/80+10




  #4

Positive perdictive value depends upon actual prevalence of disease .

But i dont know how to correlate ??? any ideas


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  #5

Hi grin,

Try to calculate the positive predictive value using the positive likelihood ratio:

Positive likelihood ratio= sensitivity divided by 1-specificity, so PLR= 0.8/1-0.9=8. Then,

1-Convert the prevalence (10%) to a ratio: 10% to 1:9

2-Multiply the first part of the ratio (1) by the positive likelihood ratio:8x1:9=8:9

3-Convert the ratio back to a percentage: 8/8+9=0.47 = 47%

Answer C. Let me know if I´m right nod


  #6

Thanks a million ,Man this concept always haunts . It makes sense. But I could nt follow he last point, uptill that was good, which is Convert the ratio back to a percentage: 8/8+9 (what rule did you appliued here) thanks again

___________________
In Life there are neither rewards nor punishments, just consequences.

  #7

Oh i get it .sorry i was a bit sleepy. smiling face

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In Life there are neither rewards nor punishments, just consequences.

  #8

nod







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