phuluong2k
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In a population of Ashkenazi Jesws, Frequency of heterozygote of Tay-sachs is 0,1
What is the probability that the first child of two individual from this population will have Taysachs disease
Knowing that both two individuals have a sibling with Taysach
A. 0,25
B. 0,11
C. 0,0625
D. 0,0025
E. Can not estimate
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| coagulative necrosis
Forum Senior
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It is 0.025 .So it is E.
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| anatomy
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E. Can not estimate
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| phuluong2k
Forum Fanatic
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IS it D
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| anatomy
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how d?
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| phuluong2k
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If the child got disease, both parent are Heterozygous
So P = 0,1 x 0,1 X 1/4 = 0, 0025
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| merrk
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I htink its 0.11
If both parents have a sibling with Tay Sachs, it means both their parents were heterozygous, so they each have 2/3 chance of being a carrier.
And 1/4 chance that their offspring will have disease
So 2/3 X 2/3 X 1/4 = 1/9 or 0.11
Correct me if I'm wrong.
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