dr_singh246 internal medicine pgy2

Topics: 235 Posts: 561
| | 12/23/04 - 02:17 PM  
 
   
 
|   #1 |
During an in vitro experiment, the membrane potential of a nerve cell is hyperpolarized to –120 mV. At that time, a transmitter, known to be inhibitory in function, is applied to the preparation and results in a depolarization of the membrane. Which of the following is the most likely reason for this occurrence? Inhibitory transmitters normally depolarize the postsynaptic membrane B. The normal response of the postsynaptic membrane to any transmitter is depolarization C. The inhibitory transmitter activates ligand-gated potassium channels D. Sodium channels become inactivated E. Calcium channels become activated
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| mjl1717 Forum Hero

Topics: 955 Posts: 5,450
| | 12/25/04 - 10:15 AM  
 
   
 
|   #2 |
I guess answer-c
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| Moctopod Forum Elite
Topics: 14 Posts: 422
| | 01/15/05 - 09:34 AM  
 
   
 
|   #3 |
Yep, I agree with mjl. At physiological pH, opening of ligand-gated K+ channels would lead to an outflow of K+ ions from the cell down their electrochemical gradient. If a neuron is hyperpolarised to this extent, however, potassium ions' electrochemical gradient is reversed, and channel opening would trigger a K+ ion influx. This would depolarise the cell.
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| phuluong2k Forum Fanatic

Topics: 714 Posts: 2,008
| | 01/21/05 - 05:21 AM  
 
   
 
|   #4 |
I go with c too Singh please tell us the answer
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| Ritalin Forum Newbie
Topics: 3 Posts: 30
| | 01/24/05 - 01:24 PM  
 
   
 
|   #5 |
This has NOTHING to do with Histology.
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| SDK Forum Fanatic
Topics: 537 Posts: 1,587
| | 01/28/05 - 08:28 AM  
 
   
 
|   #6 |
Hi singh. I think it is D.
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