Prep for USMLEPrep for USMLE Forum
   Forum    Step 1  Step 2 CK Step 2 CS Step 3  Match  IMGs Resources Search






Previous Topic | Next Topic  r 




 
Kaplan Qbank USMLE



Author6 Posts
  #1

During an in vitro experiment, the membrane potential of a nerve cell is hyperpolarized to –120 mV. At that time, a transmitter, known to be inhibitory in function, is applied to the preparation and results in a depolarization of the membrane. Which of the following is the most likely reason for this occurrence?
Inhibitory transmitters normally depolarize the postsynaptic membrane
B. The normal response of the postsynaptic membrane to any transmitter is depolarization
C. The inhibitory transmitter activates ligand-gated potassium channels
D. Sodium channels become inactivated
E. Calcium channels become activated

___________________
to love when it can be lost, to go on when progress seem futile and to believe in every fiber of your body. to live , have hope and faith and to never give in.... dr_singh246@yahoo.com

  #2

I guess answer-c

___________________
Smell the coffee! "Is That an Osler move??"

  #3

Yep, I agree with mjl. At physiological pH, opening of ligand-gated K+ channels would lead to an outflow of K+ ions from the cell down their electrochemical gradient. If a neuron is hyperpolarised to this extent, however, potassium ions' electrochemical gradient is reversed, and channel opening would trigger a K+ ion influx. This would depolarise the cell.

  #4

I go with c too


Singh please tell us the answer

  #5

This has NOTHING to do with Histology.

  #6

Hi singh.
I think it is D.

___________________
Love humans,save humans & live like humans.







You don't have permission to post.




Login or Register to post messages in this topic





















Contact | Leaders | Disclaimer | Privacy

Copyright @ Prep for USMLE. All rights reserved.