mash Forum Fanatic
Topics: 147 Posts: 1,326
| | 08/16/04 - 04:39 PM  
 
   
 
|   #2 |
25% fr tay sachs and nil fr sandhoffs
___________________ I hear and I forget. I see and I remember. I do and I understand. --Confucius
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| bm Forum Elite
Topics: 37 Posts: 421
| | 08/16/04 - 04:43 PM  
 
   
 
|   #3 |
thanks mash. my answer is 25% too. but i don't get it why there is nothing from sandhoff when both are autosomal recessive?
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| Malaysian Forum Guru
Topics: 28 Posts: 778
| | 08/17/04 - 06:23 AM  
 
   
 
|   #4 |
How is it 25%??? I'm not sure what sandhoff disease is but I'm assuming an autosomal recessive disease with no relation to tay-sach's. If parents are tay sach's carrier(Aa) and sandhoff's carrier(Ss) then how can the child get any of the diseases as the genes for both the diseases are not the same and since they are autosomal recessive conditions the most the child can be is a carrier of tay sach's or carrier of sandhoff's???
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| mash Forum Fanatic
Topics: 147 Posts: 1,326
| | 08/17/04 - 06:58 AM  
 
   
 
|   #5 |
tay sachs is def of hexosaminidase A sandhoffs is def of hexosaminidase A/B
___________________ I hear and I forget. I see and I remember. I do and I understand. --Confucius
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| bm Forum Elite
Topics: 37 Posts: 421
| | 08/17/04 - 02:15 PM  
 
   
 
|   #6 |
thanks mash. your last post cleared a lot of things about the topic for me 
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| Malaysian Forum Guru
Topics: 28 Posts: 778
| | 08/26/04 - 03:45 PM  
 
   
 
|   #7 |
I read the original question....it seems the original question clearly stated that sandhoff disease is only a mutation of B(not A) and so keeping this in mind the answer is 0%
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