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Kaplan Qbank USMLE



Author6 Posts
  #1

In the beta oxidation of Palmitic Acid, it will produces

106 ATP ( updated value )

129 ATP ( traditional value )

So Any one can tell that we have to use which value for STEP 1 exam ?


Thanks

  #2

I really hope they dont ask this (no offense) unimportant question on the exam but the way I learned it is...

palmitic acid = 16 carbons

divide by 2 and minus 1 = 7

for each 2 carbons going through beta ox you get 1Fadh2+1nadh+1accoa =(2+3+12)=17 carbons

17 x 7 = 119

add 12 carbons for that extra accoa you get = 131

and subtract 2 for converting palmitate into palmoylcoA = 129

I never learned the "New way"... can you tell me what it is, i heard something about it but I am not sure exactly...

btw in beta oxidation the enzymes are
fatty acyl coA dehydrogenase = makes fadh2
enoyl coA hydrolase = adds water accross a double bond, doesnt use or make energy
3L hy droxyacyl coA dehydrogenase = makes nadh
and beta-ketolase = make accoa
...

  #3

palmitic acid has 16 C
beta oxidation will give 8acetylcoA,7 NADH and 7FADH2
8AcetylCoA will yield--->24 NADH+8FADH2+8GTP(kreb's cycle)
1 NADH yields 3 ATPs
1 FADH2 gives 2 ATPs
(7+24)=31NADH; ( 7 + 8 )=15 FADH2;8GTP
total ATP=31*3+15*2+8=131
2 ATPs r used to activate palmitate to palmitoyl coA==>net ATP=131-2 =129

___________________
I hear and I forget. I see and I remember. I do and I understand.
--Confucius

  #4

Really i see the updated value of ATP in palmitic acid beta oxidation in ACE Mosby books and on some internet web site

C16 give 8 Acetyl CoA

7NADH, 7 FADH2

8 Acetyl CoA give 8 ATP, 24 NADH, 8 FADH2

Totally 31 NADH, 15 FADH2, 8 ATP

31 NADH = 31x 2,5 = 77,5

15FADH2 = 15 x 1,5 = 22,5

so sum = 108 ATP - 2ATP (activating palmitate) = 106 ATP

But I think that the classical value of 129 is better .

  #5

as long as you kjnow how to do both, chances are you wont see both answers as choices...

the only difference i see is that in the new system fadh2=1.5 not 2 atp
and nadh = 3 not 2.5 atp

I think the 0.5 atp per nadh or fadh2 is lost somewhere in the ETC in the new calculation ,right?

  #6

will they really ask these sort of questions??







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